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So yeah, you'd have to work it all through, but 12 seems like a pretty plausible cap - in fact I wouldn't have been surprised if it was lower. This gives me way more flexibility - to use the same example again, if in trying to get two 6s I just roll ten 1s, well OK, I'll just make 5x5x4 + 1 instead, because that uses fewer dice. Thirdly this is to make one specific expression - but to get a L9 prime, well, I have three different primes I can make, and I just spotted five different four-number expressions which will hit one of those.
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The worst case for the 6 prevents me from suffering the worst case for my 1, so I'm looking at more like 15 rolls, tops now (maybe fewer, I didn't bother looking at the 3). Well, if I rolled six 1s, I will just be able to use on of them as my 1, so I won't need more rolls to make that. The only(?) way it takes me 5 dice to make a 6 is if I roll six 1s. You can always make a 1 with just three numbers, for example (the only way you don't already have a 1 or two numbers 1 apart is 2, 4, 6 in which case you can do (2+4)/6 or similar), so in that example I'd be looking at more like 5+5+5?+3 dice, so certainly no more than 18. We can definitely make any of these with 20 rolls, because we can just make those four numbers and then get 107.įirstly, I probably won't need five dice for every number I want to make. roll five 1s - then you can do (1+1+1)x(1+1), worst case scenario) so a very naive upper limit is 20 dice. Paste a profile link (/id/ or /profiles/) to be redirected to calculator. If you get really unlucky you might need as many as five rolls to make a 6 (i.e. Well, if you don't roll those numbers, you can probably still make them from other numbers.
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So maybe you need to roll 6, 6, 3 and 1 so that you can do 6圆x3 - 1 = 107. The lower-level ones are probably the same or easier. You only need 4 numbers to make each of the L9 constants, if you can pick them (but you do need at least 4).